$\begin{align*}dS = \frac{dQ}{T}\end{align*}$
So,
$\begin{align*}S_2 - S_1 = \int_1^2 \frac{dQ}{T} = \int_{T_1}^{T_2} \frac{m c d T}{T} = \boxed{m c \ln \left(T_2/T_1 \right)}\...$
Therefore, answer (E) is correct.

Solution to 2008 Problem 33